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Worked Examples · Example 42

Q.Solve the following system of equations using Cramer's rule: 2x−3y=52x - 3y = 5; −4x+6y=−10-4x + 6y = -10.

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All three determinants are zero, so the equations are dependent and the system has infinitely many solutions.

Cramer's rule: if D≠0D\neq0 there is a unique solution; if D=0D=0 and every Dx=Dy=0D_x=D_y=0 the system has infinitely many solutions; if D=0D=0 but some Dx≠0D_x\neq0 or Dy≠0D_y\neq0 it is inconsistent (no solution).

  1. Equations: 2x−3y=5, −4x+6y=−102x-3y=5,\ -4x+6y=-10.

  2. Main determinant:

D=∣2−3−46∣=(2)(6)−(−3)(−4)=12−12=0.D = \begin{vmatrix} 2 & -3 \\ -4 & 6 \end{vmatrix} = (2)(6)-(-3)(-4) = 12-12 = 0.

  1. DxD_x:

Dx=∣5−3−106∣=(5)(6)−(−3)(−10)=30−30=0.D_x = \begin{vmatrix} 5 & -3 \\ -10 & 6 \end{vmatrix} = (5)(6)-(-3)(-10) = 30-30 = 0.

  1. DyD_y: Dy=∣25−4−10∣=(2)(−10)−(5)(−4)=−20+20=0.D_y = \begin{vmatrix} 2 & 5 \\ -4 & -10 \end{vmatrix} = (2)(-10)-(5)(-4) = -20+20 = 0. …

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