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Worked Examples · Example 27

Q.Using derivatives check whether the following functions are monotonic i. f(x)=x2f(x) = x^2 on (0,∞)(0, \infty)
ii. f(x)=x2f(x) = x^2 on (−∞,0)(-\infty, 0)
iii. f(x)=x2f(x) = x^2 on (−∞,∞)(-\infty, \infty)
iv. f(x)=x1/3f(x) = x^{1/3}

CBSENCERTSubjective· 3mImportance★★★★★
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✓ Free question

A function is monotonic on an interval if f′f' keeps a constant sign there; if f′f' changes sign, it is not monotonic.

Monotonic increasing: f′(x)≥0f'(x)\ge0 throughout; monotonic decreasing: f′(x)≤0f'(x)\le0 throughout.

  • f′f' = derivative of ff.
  1. For f(x)=x2f(x)=x^2, f′(x)=2xf'(x)=2x.
  2. (i) on (0,∞)(0,\infty): f′(x)=2x>0f'(x)=2x>0 for all x>0x>0 — constant positive sign, so monotonic (increasing).
  3. (ii) on (−∞,0)(-\infty,0): f′(x)=2x<0f'(x)=2x<0 for all x<0x<0 — constant negative sign, so monotonic (decreasing).
  4. (iii) on (−∞,∞)(-\infty,\infty): f′(x)=2xf'(x)=2x is negative for x<0x<0 and positive for x>0x>0 — the sign changes, so ff is not monotonic on R\mathbb{R}.
  5. (iv) f(x)=x1/3f(x)=x^{1/3}: f′(x)=13x−2/3=13x2/3>0f'(x)=\dfrac13 x^{-2/3}=\dfrac{1}{3x^{2/3}}>0 for all x≠0x\neq0 (and ff is continuous and increasing through 00). Constant positive sign, so monotonic (increasing) on R\mathbb{R}.
✓Final answer

  1. monotonic increasing on (0,∞)(0,\infty);
  2. monotonic decreasing on (−∞,0)(-\infty,0);
  3. not monotonic on (−∞,∞)(-\infty,\infty);
  4. x1/3x^{1/3} is monotonic increasing.

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