Skip to content
Worked Examples · Example 2
Q.

A departmental store paid annually for newspaper and television advertisements in 1990 and 2000 as shown below:

Expenditure19902000
Newspaper (in ten thousand ₹)1.32.9
Advertisement (in ₹)1.83

Using 1990 as the base year, compute a 2000 price index for newspaper and television advertisement prices.

Also compare the relative expenditure increase between the two modes of advertisements.

CBSENCERTSubjective· 3mImportance★★★★★est
5% · 2/40 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Price relative =p2000p1990×100=\frac{p_{2000}}{p_{1990}}\times100 gives a 2000 index of 223.08 for newspaper and 166.67 for television — newspaper advertisement cost rose faster.

Price index (relative) =p1p0×100=\dfrac{p_1}{p_0}\times100, where p0p_0 = base-year (1990) expenditure, p1p_1 = current-year (2000) expenditure. (Each medium is indexed on its own base.)

  1. Tabulate and compute the 2000 index for each medium.
Mode1990 (p0p_0)2000 (p1p_1)Index =p1p0×100=\frac{p_1}{p_0}\times100
Newspaper1.32.92.91.3×100=223.08\frac{2.9}{1.3}\times100=223.08
Television1.83.03.01.8×100=166.67\frac{3.0}{1.8}\times100=166.67
  1. Newspaper. 2.91.3=2.2308⇒223.08\dfrac{2.9}{1.3}=2.2308\Rightarrow 223.08 (a rise of 223.08−100=123.08%223.08-100=123.08\%). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.