Q.Pipe A can fill a tank in 30 hours and pipe B in 45 hours. If both the pipes are opened in an empty tank, how much time will it take to fill the tank?
Concept understanding — Work Rate With Leakage
Work Rate With Leakage – A First Look
Imagine you are filling a bucket with a hose. The hose pours water in at a certain speed. But there is a small hole at the bottom of the bucket — water is leaking out at the same time. How long will it actually take to fill the bucket?
That is the core idea of work rate with leakage: one agent is doing positive work (filling, building, adding), while another is doing negative work (emptying, destroying, removing). The net result is what matters.
The Intuition
If a pipe fills a tank in 6 hours, its filling rate is 61 of the tank per hour. If a leak empties the same tank in 12 hours, its emptying rate is 121 of the tank per hour.
When both are open together, the tank fills at a net rate:
Net rate=61−121=122−121=121
So together, they fill 121 of the tank per hour — meaning it takes 12 hours to fill the tank.
A common mistake is to add the rates: 61+121=41, giving 4 hours. That would be correct if both were filling. But one is emptying — you must subtract the leakage rate.
The Precise Statement
Let:
- A = time taken by the filling agent alone to complete the work (or fill the tank)
- B = time taken by the leakage alone to empty the work (or empty the tank)
Then:
- Filling rate = A1 (work per unit time)
- Leakage rate = B1 (work per unit time)
When both operate simultaneously, the net work rate is:
Net rate=A1−B1
The time taken to complete the work (fill the tank) when both are active is:
Time=A1−B11=B−AAB
This formula only works when B>A — the leakage must be slower than the filling. If B=A, the net rate is zero and the tank never fills. If B<A, the tank never fills at all (it empties faster than it fills).
A Worked Example
Problem: A tap fills a cistern in 8 hours. A leak at the bottom empties it in 12 hours. If both are opened together, how long will it take to fill the cistern?
Step 1 – Find the rates
- Filling rate: 81 cistern per hour
- Leakage rate: 121 cistern per hour
Step 2 – Net rate
81−121=243−242=241
Step 3 – Time
Time=2411=24 hours
If the problem gives you the time with leakage and asks for the leakage time alone, set up the equation: A1−B1=T1, where T is the time with leakage. Solve for B.
Why This Matters
Work rate with leakage appears in:
- Pipes and cisterns (most common)
- Workers with a helper who undoes work (e.g., a machine that occasionally breaks down)
- Projects where one team builds and another demolishes
The key is always the same: identify which agent adds and which subtracts, then work with net rate. Everything else follows from the basic idea that rate × time = work done.
Combined rate =301+451=905=181, so time =18 hours.
Both pipes together fill the tank in 18 hours.
Add the two filling rates; the reciprocal of the sum is the time =18 hours.
If a pipe fills a tank in t hours, its rate =t1 tank/hour. Combined time =sum of rates1.
- Rate of A=301 tank/h; rate of B=451 tank/h.
- Combined rate =301+451. LCD =90: =903+902=905=181 tank/h.
- Time to fill =1/181=18 hours.
Check: in 18 h, A fills 3018=53 and B fills 4518=52; total =1 tank ✓.
The tank will be filled in 18 hours.
- CBSE 2024Set 465/S/RQPS/44 marksQ.Case Study – 3 For providing water to the families of a colony, a large water tank with two inlet pipes A and B and an outlet pipe C, is installed. Pipes A and B can fill the tank in 10 hours and 12 hours respectively; whereas pipe C can empty the tank in 15 hours. Based on the above information, answer the following questions :(i) If both pipes A and B are opened together, then find the time in which the tank will be filled completely. [1](ii) If both pipes A and C are opened together, then find the time in which the tank will be filled completely. [1](iii)(a) If all the three pipes A, B and C are opened together, then find the time in which the tank will be filled completely. [2](OR)(b) Pipes A and B are opened together for some time and then pipe B is turned off after some time. If the tank is completely filled in 6 hours, then after how many hours is pipe B turned off ? [2]
›Reveal solutionSolution
A fills 101/h, B fills 121/h, C empties 151/h. Combining rates: A+B =1160 h, A+C =30 h, A+B+C =760 h; and B is shut after 4.8 h.
Rate of a pipe =time to fill/empty1 (positive for inlet, negative for outlet). Time to fill =net rate1; part filled in time t at rate r is rt.
- Rates: A =101 per hour, B =121 per hour, C =−151 per hour.
- A and B together 2. Combined rate =101+121=606+605=6011 per hour. 3. Time to fill =1160 hours.
- A and C together
4. Combined rate =101−151=303−302=301 per hour.
5. Time to fill =30 hours.
(iii)(a) A, B and C together
6. Combined rate =101+121−151=606+605−604=607 per hour.
7. Time to fill =760 hours.
(iii)(b) B turned off after t hours, tank full in 6 hours
8. A runs the full 6 hours: part filled =106. B runs only t hours: part filled =12t.
9. Total =1: 106+12t=1⇒12t=1−106=104=52.
10. t=12×52=524=4.8 hours.
✓Final answer
(i) 1160 hours. (ii) 30 hours. (iii)(a) 760 hours; (b) pipe B is turned off after 4.8 hours.
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