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Q.(a) Calculate the EMI under 'Flat Rate System' for a loan of ₹ 5,00,000 with 10% annual interest rate for 5 years.

(OR)
(b) A machine costing ₹ 2,00,000 has effective life of 7 years and its scrap value is ₹ 30,000. What amount should the company put into a sinking fund earning 5% p.a., so that it can replace the machine after its usual life ? Assume that a new machine will cost ₹ 3,00,000 after 7 years. [Given that : (1⋅05)7=1⋅407(1 \cdot 05)^7 = 1 \cdot 407]
CBSECBSE Class XII Board 2022Subjective· 4mImportance★★★★★
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  1. Total interest == ₹2,50,000, total due == ₹7,50,000 over 60 months ⇒\Rightarrow EMI == ₹12,500.
  2. Target == ₹2,70,000 (new cost −- scrap); annual deposit =270000×0.051.407−1≈=270000\times\dfrac{0.05}{1.407-1}\approx ₹33,169.53.

(a) Flat Rate System: total interest I=P⋅r⋅tI=P\cdot r\cdot t; total payable =P+I=P+I;   EMI=P+I12t\;\text{EMI}=\dfrac{P+I}{12t}, where P=P= principal, r=r= annual rate, t=t= years.

(b) Sinking fund: A=P⋅(1+i)n−1iA = P\cdot\dfrac{(1+i)^n-1}{i}, where A=A= amount to be accumulated, P=P= periodic (annual) deposit, i=i= rate per period, n=n= number of periods.

Part (a) — Flat Rate EMI

  1. Given P=5,00,000P=5{,}00{,}000, r=10%=0.10r=10\%=0.10 p.a., t=5t=5 years.
  2. Total (flat) interest: I=P⋅r⋅t=500000×0.10×5=250000I=P\cdot r\cdot t=500000\times 0.10\times 5 = 250000.
  3. Total amount repayable: P+I=500000+250000=750000P+I=500000+250000=750000.
  4. Number of monthly instalments: 12×5=6012\times 5 = 60.
  5. EMI =75000060=12500=\dfrac{750000}{60}=12500.

Part (b) — Sinking Fund …

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