Q.State whether the following statement is True or False: If the feasible region for a LPP is unbounded, maximum or minimum of the objective function Z=ax+by may or may not exist.
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Unbounded Feasible Region
Stand in an open field and you can walk as far as you like in some direction without ever hitting a wall. Stand in a closed hall and walls stop you on every side. A feasible region in linear programming is the set of all points satisfying every constraint; calling it unbounded means that in at least one direction you can keep moving forever and still stay inside it.
Unbounded does not mean "huge area" — it means the region has no boundary in some direction, so it stretches off to infinity there.
How a region becomes unbounded
Each constraint is a linear inequality such as x≥0, y≥0, or x+y≤10, and each cuts the plane into a half-plane. The feasible region is the overlap of these half-planes. If the constraints fail to "close off" the region in some direction, it runs on without end.
Example. With only x≥0 and y≥0, the region is the entire first quadrant — you can travel as far as you wish along either axis, so it is unbounded. Add x+y≤10 and the region shrinks to the triangle with vertices (0,0), (10,0), (0,10) — now bounded.
Why it matters for the objective
In an LP problem you maximise or minimise Z=ax+by over the feasible region.
- If the region is bounded, both the maximum and the minimum of Z exist and each occurs at a corner point.
- If the region is unbounded, an optimum may fail to exist — you might push Z larger and larger by moving out along the open direction.
An unbounded region does not automatically destroy the answer. For Z=−x+y on the first quadrant, as x→∞ the term −x drives Z→−∞, so a maximum can still sit at a corner. Always compare the objective's direction with the open direction of the region.
Exam technique
- Graph the constraints and evaluate Z at every corner point. …
An unbounded feasible region stretches to infinity in some direction, so a corner value is the optimum only if the objective cannot improve past it in that open direction.
- If Z=ax+by can keep improving as you move outward, the optimum does not exist.
- If it cannot (the region is capped in the objective's direction), the optimum exists at a corner. …
True. An unbounded feasible region does not by itself decide the question — whether Z=ax+by attains a maximum or a minimum depends on the direction of the objective relative to the open direction of the region.
What "unbounded" means
A feasible region is unbounded when it stretches to infinity in at least one direction — you can keep moving inside it without ever crossing a boundary.
Why the optimum may or may not exist
Evaluate Z at the corner points to get a candidate value M, then, because the region is open in some direction, run the extra graphical check:
- For a maximum: if the half-plane ax+by>M still meets the region, Z can be pushed higher without end, so no maximum exists; if it misses the region, M is the maximum.
- For a minimum: do the same test with ax+by<M.
Both outcomes are genuinely possible: …
Method: Judging a True/False claim about unbounded optima
For a True/False statement about optima on an unbounded region, test it against the actual rule rather than a gut reaction.
The reasoning pattern
Step 1: State the precise rule.
On a bounded region a linear Z=ax+by always attains both a max and a min. On an unbounded region the optimum may exist and may fail to exist -- it depends on the direction of (a,b) relative to the open direction of the region.
Step 2: Compare the claim to the rule. …
Common Mistakes
Mistake 1: Marking the statement False on the belief that "unbounded means no optimum."
Why it's wrong: an unbounded region does not forbid an optimum; whether the max or min exists depends on the direction of the objective relative to the open direction -- it may exist or may not. That is exactly what the statement says, so it is …
- CBSE 2025Set 65/1/11 markMCQQ.If the feasible region of a linear programming problem with objective function Z=ax+by, is bounded, then which of the following is correct ? (A) It will only have a maximum value. (B) It will only have a minimum value. (C) It will have both maximum and minimum values. (D) It will have neither maximum nor minimum value.
›Reveal solutionSolution
For a linear programming problem with a bounded feasible region, the objective function Z=ax+by must attain both a maximum and a minimum value on that region. The correct option is (C).
Why this is true — the core idea
The key is the word bounded. A bounded feasible region means the entire region can be enclosed inside some large circle (or rectangle). It doesn't stretch off to infinity in any direction. When the region is bounded, the objective function Z=ax+by — which is a linear function — is continuous. A famous theorem from calculus (the Extreme Value Theorem) says that a continuous function on a closed and bounded set always attains both a maximum and a minimum value.
In linear programming, the feasible region is always closed (it includes its boundary lines). So if it's also bounded, both extreme values exist.
Watch outA common mistake is to think that a bounded region guarantees only one extreme value (either max or min). That would only happen if the objective function is constant on the entire region — but then it still has both, just equal to each other. So "both" is still correct.
Step-by-step reasoning
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What does "bounded" mean here?
A region is bounded if you can draw a big enough circle that completely covers it. For example, a triangle or a pentagon is bounded. A region that goes on forever (like a half-plane or an unbounded ray) is unbounded.
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What does the objective function look like?
Z=ax+by is a linear function. Its graph is a plane tilted in 3D. On the 2D feasible region, it produces a "height" at every point. As you move across the region, this height changes linearly.
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What happens on a bounded region? …
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- CBSE 2025Set 65/4/11 markMCQQ.Assertion (A) : If the feasible region is empty in a Linear Programming Problem (LPP), then the LPP has no solution. Reason (R) : Feasible region is the region in which all the constraints are satisfied. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true.
›Reveal solutionSolution
The key idea is that an empty feasible region means no point satisfies all constraints, so the LPP has no solution. Both Assertion (A) and Reason (R) are true, and Reason (R) correctly explains Assertion (A). The correct option is (A).
Concept and Intuition
In Linear Programming, the feasible region is the set of all points that satisfy every constraint — including non-negativity conditions. If this region is empty, it means the constraints are contradictory; no point in the plane (or space) can meet all of them simultaneously. Naturally, if there’s no point to evaluate the objective function on, the problem cannot have a solution — neither a maximum nor a minimum. This is a fundamental logical consequence, not a subtle technicality.
The Reason (R) simply defines what a feasible region is. That definition is the very basis for why an empty region leads to no solution. So (R) is not just true — it’s the direct explanation of (A).
Step-by-step reasoning
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Understand Assertion (A):
“If the feasible region is empty in an LPP, then the LPP has no solution.”
This is a standard result. An LPP’s solution (optimal value) must lie within the feasible region. If the region has no points, there is no candidate for an optimal solution. Hence the LPP is infeasible — it has no solution.
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Understand Reason (R):
“Feasible region is the region in which all the constraints are satisfied.”
This is the textbook definition. Every constraint — including non-negativity — must hold. The feasible region is the intersection of all half-planes (or half-spaces) defined by the constraints.
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Check the truth of (A):
True. An empty feasible region implies no point satisfies all constraints, so no feasible solution exists. Therefore the LPP has no solution.
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Check the truth of (R):
True. The definition is correct.
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Check if (R) correctly explains (A): …
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- CBSE 2024Set 65/2/11 markMCQQ.The common region determined by all the constraints of a linear programming problem is called: (A) an unbounded region (B) an optimal region (C) a bounded region (D) a feasible region
›Reveal solutionSolution
The set of all points satisfying every constraint in a linear programming problem is called the feasible region — it's where all candidate solutions live. The answer is (D).
Understanding the Feasible Region
When you set up a linear programming problem, you're essentially drawing boundaries on a coordinate plane. Each constraint — whether it's an inequality like 2x+3y≤12 or a non-negativity condition like x≥0 — carves out a half-plane. The region where all these half-planes overlap is special: it contains every point that respects every single rule you've laid down.
This overlap region has a name that captures its essence: it's the set of all feasible solutions, meaning solutions that are actually allowed by the problem's constraints. Not all of these solutions are optimal (that's what we're trying to find), but they're all valid candidates.
Why Each Term Means What It Does
Let me walk through what each option actually describes:
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Feasible region (Option D): This is the technical term for the common region determined by all constraints. A point is feasible if and only if it satisfies every constraint simultaneously. This is the fundamental concept in linear programming — before we can maximize or minimize an objective function, we need to know where we're allowed to look.
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Bounded vs. Unbounded (Options A and C): These are properties that a feasible region might have, not names for the region itself. A feasible region is bounded if it fits inside some large enough circle — think of a triangle or polygon. It's unbounded if it stretches infinitely in some direction — imagine the region x≥0,y≥0,x+y≥5, which extends forever to the upper-right. Both types are still called feasible regions; bounded/unbounded just describes their shape. …
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- CBSE 2026Set ANNUAL1 markQ.What is meant by bounded region of a LPP?
›Reveal solutionSolution
A bounded region is a feasible region that has finite extent — it can be enclosed inside some circle.
In a Linear Programming Problem, the feasible region is the set of all points satisfying the constraints. This region is said to be bounded if it can be enclosed within a circle of finite radius — i.e. it does not extend to infinity in any direction. (If it cannot be so enclosed, it is called an unbounded region.)
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