Q.A straight rail track made of steel, of length m, is clamped rigidly to a railway line at both of its ends so that it cannot expand freely. On a summer day the temperature rises by C, so the track's natural expansion has nowhere to go and it buckles: it takes the shape of two equal straight segments meeting at the centre, which is pushed out by a distance from the original straight line. The distance between the two clamped ends stays fixed at , while each of the two buckled segments has length , where is the total increase in the track's length caused by the heating. Taking the coefficient of linear expansion of steel as , find , the displacement of the centre.
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Start your 14-day free trial to unlock the full solution →Because both ends are clamped, the steel cannot lengthen when heated, so its thermal expansion forces it to bow out. The buckled track forms two equal straight arms of length on a base that is still , and the centre lifts by . Applying Pythagoras to one half and using gives m.
Concept
A freely heated rod would grow by . Here the ends are fixed, so the extra length has nowhere to go along the line; the track relieves it by bending out of the straight line (buckling). The material length becomes , split into two equal straight arms meeting at the raised centre, while the straight-line distance between the clamps is still .
Geometry (why Pythagoras)
Each arm is the hypotenuse of a right triangle whose base is half the clamp separation, , and whose height is the centre displacement :
Solving for :
Steps
- Thermal expansion: …
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