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Exercise 5.1 · Q14

Q.37−(3x+5)>9x−8(x−3)37 - (3x + 5) > 9x - 8(x - 3)

Chhattisgarh CgbseTextbookSubjective· 2mImportance★★★★★
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Simplify both sides by distributing and combining like terms, then isolate xx to find that x<2x < 2.

Linear inequalities work exactly like equations when you add, subtract, multiply, or divide—with one critical exception: multiplying or dividing by a negative number flips the inequality sign. The strategy is to simplify both sides first, then collect all terms with the variable on one side and constants on the other.

Let's start by expanding and simplifying each side of the inequality.

Left side:

37−(3x+5)=37−3x−5=32−3x37 - (3x + 5) = 37 - 3x - 5 = 32 - 3x

Right side:

9x−8(x−3)=9x−8x+24=x+249x - 8(x - 3) = 9x - 8x + 24 = x + 24

Now the inequality becomes:

32−3x>x+2432 - 3x > x + 24

With both sides simplified, we can solve for xx systematically.

  1. Move all terms containing xx to one side. Subtract xx from both sides:

32−3x−x>2432 - 3x - x > 24

32−4x>2432 - 4x > 24

  1. Isolate the term with xx. Subtract 3232 from both sides:

−4x>24−32-4x > 24 - 32

−4x>−8-4x > -8

  1. Solve for xx by dividing both sides by −4-4. …

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