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Exercise 5.1 · Q2

Q.Solve −12x>30-12x > 30, when

(i) xx is a natural number.
(ii) xx is an integer.
Chhattisgarh CgbseTextbookSubjective· 2mImportance★★★★★
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✓ Free question

Dividing both sides of −12x>30-12x > 30 by −12-12 reverses the inequality to give x<−52x < -\frac{5}{2}. Natural numbers are all positive, so (i) has no solution; integers less than −2.5-2.5 give (ii) the solution x∈{…,−5,−4,−3}x \in \{\ldots, -5, -4, -3\}.

Understanding Linear Inequalities with Negative Coefficients

When you multiply or divide both sides of an inequality by a negative number, the inequality sign flips direction. This is the heart of solving −12x>30-12x > 30. Think of it this way: if a>ba > b, then −a<−b-a < -b (the larger number becomes more negative, hence smaller). The same principle applies when isolating xx.

Let me solve the inequality first, then apply the constraints on xx.

Solving the Inequality

1. Isolate xx by dividing both sides by −12-12

Starting with:

−12x>30-12x > 30

Divide both sides by −12-12. Since we're dividing by a negative number, the inequality reverses:

x<30−12x < \frac{30}{-12}

2. Simplify the fraction

x<−3012=−52=−2.5x < -\frac{30}{12} = -\frac{5}{2} = -2.5

So the general solution is x<−2.5x < -2.5, meaning xx can be any real number strictly less than −2.5-2.5.

Watch out

The most common mistake here is forgetting to flip the inequality sign when dividing by −12-12. If you write x>−2.5x > -2.5 instead, you'll get the wrong solution set entirely.

Applying the Constraints

Now we restrict xx to specific number sets.

(i) When xx is a natural number

Natural numbers are N={1,2,3,4,…}\mathbb{N} = \{1, 2, 3, 4, \ldots\} — the positive counting numbers (some definitions include 00, but the standard Indian curriculum uses N={1,2,3,…}\mathbb{N} = \{1, 2, 3, \ldots\}).

We need natural numbers that satisfy x<−2.5x < -2.5. But every natural number is positive, and −2.5-2.5 is negative. No positive number can be less than a negative number.

Solution for (i): There is no natural number satisfying the inequality. The solution set is ∅\emptyset (the empty set).

(ii) When xx is an integer

Integers are Z={…,−3,−2,−1,0,1,2,3,…}\mathbb{Z} = \{\ldots, -3, -2, -1, 0, 1, 2, 3, \ldots\} — all whole numbers, positive, negative, and zero.

We need integers satisfying x<−2.5x < -2.5. Since −2.5-2.5 lies between −3-3 and −2-2, the integers less than −2.5-2.5 are:

…,−5,−4,−3\ldots, -5, -4, -3

In other words, all integers less than or equal to −3-3.

Solution for (ii): x∈{…,−5,−4,−3}x \in \{\ldots, -5, -4, -3\} or in interval notation, x∈(−∞,−3]∩Zx \in (-\infty, -3] \cap \mathbb{Z}.

Tip

When converting a strict inequality like x<−2.5x < -2.5 to integers, find the largest integer strictly less than −2.5-2.5. That's −3-3. Then all integers to the left (more negative) also work.

✓Final answer

(i) No natural number satisfies the inequality; the solution set is empty. (ii) The integer solutions are x∈{…,−5,−4,−3}x \in \{\ldots, -5, -4, -3\}, i.e., all integers less than or equal to −3-3.

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