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Worked Examples · Example 2

Q.₹1,000 is deposited at the beginning of each year for 3 years in a fund earning 10% per annum compounded annually. Find the amount at the end of 3 years, and compare it with the corresponding ordinary annuity.

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Method 1 — Annuity-due formula.

P=1000P = 1000, i=0.10i = 0.10, n=3n = 3, payments in advance.

Atextordinary=1000left[dfrac(1.10)3−10.10right]=1000left[dfrac1.331−10.10right]=1000times3.31=3310A_{\\text{ordinary}} = 1000\\left[\\dfrac{(1.10)^3-1}{0.10}\\right] = 1000\\left[\\dfrac{1.331-1}{0.10}\\right] = 1000\\times3.31 = 3310

Atextdue=Atextordinary(1+i)=3310times1.10=3641A_{\\text{due}} = A_{\\text{ordinary}}(1+i) = 3310\\times1.10 = 3641

The annuity due (₹3,641) exceeds the ordinary annuity (₹3,310) by exactly one period's interest, because every advance payment stays invested one year longer.

✓Final answer

The amount of the annuity due is ₹3,641, which is ₹331 more than the ₹3,310 an ordinary annuity of the same size would give.

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