Q.A company must replace a machine costing ₹1,00,000 at the end of 5 years. It decides to build a sinking fund by depositing an equal sum at the end of each year into an account earning 12% per annum compounded annually. Find the annual deposit.
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Sinking Fund
A sinking fund is money set aside at regular intervals so that, with compound interest, it grows to a known amount needed on a future date — for example to replace an asset or redeem a debt. It is a direct application of the future value of an annuity.
A sinking fund runs the annuity idea in reverse: you know the target future amount and solve for the fixed instalment that will build up to it.
How it works
If you deposit a fixed sum P at the end of each period, those deposits compound into an accumulated value given by the annuity factor. To find the instalment required to hit a target A, simply rearrange that relationship.
The target must be the future cost (the replacement price prevailing at the end of the term), never the present cost.
Accumulated value of deposits: A=P[i(1+i)n−1].
Instalment needed for a target A:
P=A×(1+i)n−1i
i = rate per period, n = number of deposits.
Steps
- Fix the target future amount A (the replacement cost at term-end).
- Identify the rate per period i and the number of deposits n.
- Substitute into P=A⋅(1+i)n−1i to get each instalment.
Quick example
A firm needs ₹33,100 in 3 years to replace a machine. Deposits earn 10% p.a. What annual deposit is required?
- A=33100, i=0.10, n=3. …
A sinking fund is a future-value annuity solved backwards: the target amount is known, and we find the equal deposit that accumulates to it using the sinking-fund factor.
P=Adfraci(1+i)n−1=100000timesdfrac0.12(1.12)5−1. …
Method 1 — Sinking-fund formula.
A=100000 (amount needed at end), i=0.12, n=5.
P=Aleft[dfraci(1+i)n−1right]=100000left[dfrac0.12(1.12)5−1right] …
Method 2 — Accumulate the deposit forward (cross-check). Feed the deposit back into the ordinary future-value annuity formula of §2 and confirm it reaches the target:
A=Pleft[dfrac(1+i)n−1iright]=15740.97left[dfrac1.762342−10.12right]=15740.97times6.352847=1,00,000 …
A common confusion is to use the present-value (loan) formula for a sinking fund. A sinking fund accumulates toward a future amount, so it uses the future-value relationship; using the present-value factor would an …
- CA Foundation 2026Set jan-20261 markMCQQ.A sinking fund is created for replacement of machine at the end of 20 years. Its present cost is ₹ 8,00,000. After 20 years cost of new machine would be ₹ 10,00,000. How much provision need to be made out of the profit each year provided sinking fund investments can earn interest at the rate of 7% pa? The scrap value of the machine at the end of 20 years would be ₹ 2,00,000. Given 1.0720=3.8697. (A) ₹ 15,514 (B) ₹ 13,514 (C) ₹ 19,514 (D) ₹ 17,514
›Reveal solutionSolution
Net fund needed =10,00,000−2,00,000=₹8,00,000; annuity factor =0.071.0720−1=40.9957; annual provision =800000/40.9957≈₹19,514.
Step 1 — amount the fund must reach
The scrap value of the old machine (₹2,00,000) offsets the cost of the new machine (₹10,00,000), so the fund must provide:
10,00,000−2,00,000=₹8,00,000.
(The present cost ₹8,00,000 is extra data not needed for the accumulation.)
Step 2 — annuity accumulation factor at 7% for 20 years
0.07(1.07)20−1=0.073.8697−1=0.072.8697=40.9957.
Step 3 — annual sinking-fund provision
A=40.99578,00,000≈₹19,514. …
- CA Foundation 2025Set jan-20251 markMCQQ.Sunil plans to save for his higher studies. He wants to accumulate a sum of ₹ 5,00,000 at the end of 10 years. How much amount should he invest every year if the interest rate is 10% compounded annually ? (Given that (1.1)10=2.593742) (A) ₹ 31,372.71 (B) ₹ 3,137.27 (C) ₹ 31,312.71 (D) ₹ 3,000.32
›Reveal solutionSolution
Sinking fund: A=(1.1)10−1FV⋅i=15.93742500000=₹31,372.71.
Step 1 — Identify the sinking-fund structure
Equal annual investments A must grow to a target FV=₹5,00,000 over n=10 years at i=10%=0.1.
Step 2 — Future value of annuity factor
FV=A⋅i(1+i)n−1
0.1(1.1)10−1=0.12.593742−1=0.11.593742=15.93742
Step 3 — Solve for the annual deposit
A=15.93742500000=31372.71
Why the other options are wrong: (B) ₹3,137.27 and (D) ₹3,000.32 are off by a factor of 10; (C) ₹31,312.71 is a rounding/arithmetic slip on the same factor. …
- CA Foundation 2025Set jan-20251 markMCQQ.How much amount is required to be invested every year so as to accumulate ₹ 15,00,000 at the end of 20 years if interest is compounded annually at 10% ? [Given A(n,i)=57.274999] (A) ₹ 26,189.44 (B) ₹ 29,190.35 (C) ₹ 24,155.35 (D) ₹ 30,698.44
›Reveal solutionSolution
Sinking fund: annual instalment R=A(n,i)Target=57.27499915,00,000=₹26,189.44.
Step 1 — Recognise the sinking fund
We need equal annual deposits that grow to a target future value — that is a sinking fund, i.e. an ordinary annuity whose future value is known.
FV=R×i(1+i)n−1=R×A(n,i)
Step 2 — Substitute the values
15,00,000=R×57.274999
Step 3 — Solve for the instalment
R=57.27499915,00,000=₹26,189.44 …
- CA Foundation 2025Set may-20251 markMCQQ.How much approximate amount should you save annually to accumulate ₹ 20,00,000 by the end of 12 years, if the saving earns an interest of 14 percent compound annually ? [Given that (1.14)12=4.8179] (A) ₹ 4,15,118 (B) ₹ 5,23,848 (C) ₹ 73,339 (D) ₹ 1,11,200
›Reveal solutionSolution
Annual saving = Target ÷ annuity accumulation factor = ₹20,00,000 ÷ 27.27 ≈ ₹73,339.
Step 1 — Recognise the sinking fund (FV of annuity)
Equal yearly deposits compounding to reach a fixed future target is a sinking-fund problem. The accumulated value of an ordinary annuity is
FV=P×i(1+i)n−1
Step 2 — Substitute the data
FV=20,00,000, i=0.14, n=12, (1.14)12=4.8179.
i(1+i)n−1=0.144.8179−1=0.143.8179=27.2707
Step 3 — Solve for the annual saving
P=27.2707FV=27.270720,00,000≈₹73,339 …
- CA Foundation 2024Set sep-20241 markMCQQ.What is the annual contribution required by an organization to accumulate ₹ 20,00,000 in ten years for the construction of a new manufacturing plant, utilizing a sinking fund with an annual interest rate of 6% compounded annually ? {Where A(10, 0.06) = 13.180785} (A) ₹ 1,51,736.03 (B) ₹ 1,67,440.90 (C) ₹ 1,75,433.60 (D) ₹ 1,83,714.28
›Reveal solutionSolution
Annual deposit = Target ÷ future-value-of-annuity factor = ₹20,00,000 ÷ 13.180785 = ₹1,51,736.03.
Step 1 — The sinking-fund relation
Each year an equal amount P is set aside and earns 6% compounded annually. After 10 years the deposits accumulate to the future value of an ordinary annuity:
FV=P×i(1+i)n−1=P×A(n,i)
Step 2 — Substitute the known values
Here the target FV=₹20,00,000 and the factor A(10,0.06)=13.180785 is supplied.
P=A(10,0.06)FV=13.18078520,00,000
Step 3 — Compute the deposit
P=₹1,51,736.03 …
- CA Foundation 2023Set jun-20231 markMCQQ.A company want to replace its existing tool room machine at the end of 10 years, the expected cost of machine would be ₹ 10,00,000. If management of the company creates a sinking fund, how much provision needs to be made out of revenue each year which can earn at the rate of 10% compounded annually? Given A(10,0.10) = 15.937425. (A) ₹ 74,625 (B) ₹ 72,514 (C) ₹ 62,745 (D) ₹ 67,245
›Reveal solutionSolution
Annual deposit =A(10,0.10)Future value=15.93742510,00,000=₹62,745.
Step 1 — Recall the sinking-fund relation
The future value of n equal deposits D is D×A(n,i), where A(n,i)=i(1+i)n−1. Set this equal to the required corpus:
D×A(10,0.10)=10,00,000.
Step 2 — Substitute the given factor
D×15.937425=10,00,000.
Step 3 — Solve for the annual provision
D=15.93742510,00,000=62,745.4≈₹62,745. …
- CA Foundation 2022Set dec-20221 markMCQQ.How much amount is required to be invested every year so as to accumulate ₹ 5,00,000 at the end of 12 years if interest is compounded annually at 10%? [Where A (12, 0.1) = 21.384284] (A) ₹ 23381.65 (B) ₹ 24385.85 (C) ₹ 26381.65 (D) ₹ 28362.75
›Reveal solutionSolution
P = 5,00,000 ÷ 21.384284 ≈ ₹23,381.65.
Step 1 — Set up the accumulation equation
The future value of an ordinary annuity is FV=P×i(1+i)n−1=P×A(n,i).
5,00,000=P×21.384284
Step 2 — Solve for the annual deposit
P=21.3842845,00,000=₹23,381.65
Watch outA(12,0.1) is the accumulation factor for a series of deposits — divide the target corpus by it. Multiplying gives an absurdly large figure. …
- CA Foundation 2022Set dec-20221 markMCQQ.Sinking fund factor is the reciprocal of: (A) Present value interest factor of a single cash flow (B) Present value interest factor of an annuity (C) Future value interest factor of an annuity (D) Future value interest factor of a single cash flow
›Reveal solutionSolution
Sinking fund factor =(1+i)n−1i=FVIFA1.
Step 1 — FVIFA
FVIFA=i(1+i)n−1
turns an annuity into its future value: FV=A×FVIFA.
Step 2 — Sinking fund factor
To accumulate a target FV, the required deposit is
A=FV×(1+i)n−1i.
The multiplier (1+i)n−1i is the sinking fund factor.
Step 3 — Recognise the reciprocal
Sinking fund factor=FVIFA1.
Watch outDo not confuse it with the capital-recovery factor (reciprocal of the PRESENT-value annuity factor). Sinking fund is about building up a FUTURE sum, so it pairs with the future-value factor. …
- CA Foundation 2021Set dec-20211 markMCQQ.Mr. X wants to accumulate ₹ 50,00,000 at the end of 10 years. Then how much amount is required to be invested every year if interest is compounded annually at 10%? (Given that P(10,0.10)=15.9374298) (A) ₹ 3,13,726.87 (B) ₹ 4,13,726.87 (C) ₹ 3,53,726.87 (D) ₹ 4,53,726.87
›Reveal solutionSolution
Deposit = target ÷ annuity factor = 50,00,000 ÷ 15.9374298 ≈ ₹3,13,726.87.
Step 1 — Identify the sinking fund relation
A constant year-end deposit A for 10 years at 10% accumulates to
FV=A×i(1+i)n−1=A×P(10,0.10).
Step 2 — Solve for A
A=P(10,0.10)FV=15.937429850,00,000≈3,13,726.87.
Watch outDo not multiply by the factor — that would give the future value of a ₹50 lakh annuity. Here ₹50 lakh IS the future value, so divide. …
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