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Worked Examples · Example 11

Q.A sum of ₹5,000 is invested at 8% per annum compound interest for 5 years. Using logarithms (given log⁡1.08=0.0334\log 1.08 = 0.0334, log⁡5=0.6990\log 5 = 0.6990, and antilog 0.8661=7.3470.8661 = 7.347), find the compound amount and the compound interest.

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The compound-amount formula is

A=P(1+r100)n=5000 (1.08)5.A = P\left(1 + \dfrac{r}{100}\right)^{n} = 5000\,(1.08)^{5}.

Take logarithms of both sides (product and power laws):

log⁡A=log⁡5000+5log⁡1.08.\log A = \log 5000 + 5\log 1.08.

Now log⁡5000=log⁡(5×1000)=log⁡5+3=0.6990+3=3.6990\log 5000 = \log(5\times1000) = \log 5 + 3 = 0.6990 + 3 = 3.6990, and 5log⁡1.08=5×0.0334=0.16705\log 1.08 = 5\times0.0334 = 0.1670. So

log⁡A=3.6990+0.1670=3.8660≈3.8661.\log A = 3.6990 + 0.1670 = 3.8660 \approx 3.8661.

Take the antilogarithm: the mantissa 0.8661 gives digits 7347, and the characteristic 3 gives 4 digits before the point: …

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