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Worked Examples · Example 12

Q.Using logarithms, evaluate 25.36×18.56.4\dfrac{25.36 \times 18.5}{6.4}. (Given log⁡25.36=1.4041\log 25.36 = 1.4041, log⁡18.5=1.2672\log 18.5 = 1.2672, log⁡6.4=0.8062\log 6.4 = 0.8062, and antilog 0.8651=7.3310.8651 = 7.331.)

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Let x=25.36×18.56.4x = \dfrac{25.36 \times 18.5}{6.4}. Take logarithms (product and quotient laws):

log⁡x=log⁡25.36+log⁡18.5−log⁡6.4.\log x = \log 25.36 + \log 18.5 - \log 6.4.

Substitute the given table values:

log⁡x=1.4041+1.2672−0.8062.\log x = 1.4041 + 1.2672 - 0.8062.

Add the numerator logs: 1.4041+1.2672=2.67131.4041 + 1.2672 = 2.6713. Subtract the denominator log: 2.6713−0.8062=1.86512.6713 - 0.8062 = 1.8651. …

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