Q.Write a complete Java program that prints your school's name on the screen, and briefly explain the purpose of the main method and System.out.println.

Every Java program lives inside a class and starts running at main; printing to the screen is done with System.out.println.

public class SchoolName {
    public static void main(String[] args) {
        System.out.println("Government Higher Secondary School");
    }
}

The program:

public class SchoolName {
    public static void main(String[] args) {
        System.out.println("Government Higher Secondary School");
    }
}

How it works, line by line:

• public class SchoolName { ... } — every Java program must be inside a class. The file is saved as SchoolName.java, matching the public class name.
• public static void main(String[] args) — this is the main method, the program's starting point. When the program runs, the JVM always looks for main first and begins executing there. If a program has no main, it cannot run.
• System.out.println("Government Higher Secondary School"); — System.out.println prints the text inside the double quotes to the screen and then moves the cursor to a new line. The statement ends with a semicolon ;.

To run it in an IDE: type the code, press Compile/Build, then Run; the school name appears in the console.

System.out.print(...) prints without moving to a new line, so several prints appear on one line; System.out.println(...) adds the new line at the end. Either is acceptable here.

Forgetting the semicolon at the end of the statement, saving the file with a name different from the public class, or writing Main/MAIN instead of main (Java is case-sensitive, so only main is recognised as the entry point).