Q.Write a Java program using an if...else if ladder that reads a student's marks (0–100) and prints the division: 75 and above → "Distinction", 60–74 → "First Division", 35–59 → "Pass", below 35 → "Fail".

Several ranges must be tested in the right order, from the strictest condition downward.

Complete program:

import java.util.Scanner;

public class Division {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.print("Enter marks (0-100): ");
        int marks = sc.nextInt();

        if (marks >= 75) {
            System.out.println("Distinction");
        } else if (marks >= 60) {
            System.out.println("First Division");
        } else if (marks >= 35) {
            System.out.println("Pass");
        } else {
            System.out.println("Fail");
        }
    }
}

Why the order matters. The ladder is checked top to bottom, and the first true condition wins. So the strictest test (>= 75) must come first. If we wrongly put >= 35 first, then a mark of 80 would satisfy >= 35 immediately and print "Pass" — never reaching "Distinction". Ordering from the highest cut-off downward guarantees each mark lands in exactly one band. …

The same logic can be written with nested if statements, but the if...else if ladd …

Ordering the conditions from lowest to highest (e.g. >=35 first), which sends every passing mark to the first band. Also using > instead of >= at the …