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Worked Examples · Example 3

Q.Find the minors and cofactors of the elements of the second row of A=(1230−14215)A=\begin{pmatrix} 1 & 2 & 3 \\ 0 & -1 & 4 \\ 2 & 1 & 5 \end{pmatrix}, and hence evaluate ∣A∣|A|.

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Minors of row 2. Deleting row 2 and the relevant column from AA: M21=∣2315∣=2(5)−3(1)=7,M22=∣1325∣=1(5)−3(2)=−1,M23=∣1221∣=1(1)−2(2)=−3.M_{21}=\begin{vmatrix} 2 & 3 \\ 1 & 5 \end{vmatrix}=2(5)-3(1)=7,\quad M_{22}=\begin{vmatrix} 1 & 3 \\ 2 & 5 \end{vmatrix}=1(5)-3(2)=-1,\quad M_{23}=\begin{vmatrix} 1 & 2 \\ 2 & 1 \end{vmatrix}=1(1)-2(2)=-3.

Cofactors of row 2. Using Cij=(−1)i+jMijC_{ij}=(-1)^{i+j}M_{ij}: C21=(−1)2+1(7)=−7,C22=(−1)2+2(−1)=−1,C23=(−1)2+3(−3)=3.C_{21}=(-1)^{2+1}(7)=-7,\qquad C_{22}=(-1)^{2+2}(-1)=-1,\qquad C_{23}=(-1)^{2+3}(-3)=3.

Expansion along row 2. The entries of row 2 are 0,−1,40,-1,4, so ∣A∣=(0)(−7)+(−1)(−1)+(4)(3)=0+1+12=13.|A| = (0)(-7) + (-1)(-1) + (4)(3) = 0 + 1 + 12 = 13. …

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