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Worked Examples · Example 6

Q.Using Cramer's Rule, solve the system of equations x+y+z=6, 2x−y+z=3, x+2y−z=2x+y+z=6,\ 2x-y+z=3,\ x+2y-z=2.

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Coefficient determinant. D=∣1112−1112−1∣=1∣−112−1∣−1∣211−1∣+1∣2−112∣=1(−1)−1(−3)+1(5)=−1+3+5=7.D=\begin{vmatrix} 1 & 1 & 1 \\ 2 & -1 & 1 \\ 1 & 2 & -1 \end{vmatrix} = 1\begin{vmatrix}-1&1\\2&-1\end{vmatrix} - 1\begin{vmatrix}2&1\\1&-1\end{vmatrix} + 1\begin{vmatrix}2&-1\\1&2\end{vmatrix} = 1(-1)-1(-3)+1(5) = -1+3+5=7.

DxD_x — replace the xx-coefficient column (1,2,1)(1,2,1) with the constants (6,3,2)(6,3,2). Dx=∣6113−1122−1∣=6(−1)−1(−5)+1(8)=−6+5+8=7.D_x=\begin{vmatrix} 6 & 1 & 1 \\ 3 & -1 & 1 \\ 2 & 2 & -1 \end{vmatrix} = 6(-1)-1(-5)+1(8) = -6+5+8=7.

DyD_y — replace the yy-coefficient column (1,−1,2)(1,-1,2) with the constants. Dy=∣16123112−1∣=1(−5)−6(−3)+1(1)=−5+18+1=14.D_y=\begin{vmatrix} 1 & 6 & 1 \\ 2 & 3 & 1 \\ 1 & 2 & -1 \end{vmatrix} = 1(-5)-6(-3)+1(1) = -5+18+1=14.

DzD_z — replace the zz-coefficient column (1,1,−1)(1,1,-1) with the constants. Dz=∣1162−13122∣=1(−8)−1(1)+6(5)=−8−1+30=21.D_z=\begin{vmatrix} 1 & 1 & 6 \\ 2 & -1 & 3 \\ 1 & 2 & 2 \end{vmatrix} = 1(-8)-1(1)+6(5) = -8-1+30=21. …

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