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Worked Examples · Example 1

Q.Verify that F(x)=x44−3xF(x) = \dfrac{x^{4}}{4} - 3x is an antiderivative of f(x)=x3−3f(x)=x^{3}-3, and hence write down ∫(x3−3) dx\displaystyle\int (x^{3}-3)\,dx.

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✓ Free question

Step 1 — differentiate the candidate F(x)F(x):

F(x)=x44−3x⇒F′(x)=4x34−3=x3−3F(x)=\frac{x^{4}}{4}-3x \quad\Rightarrow\quad F'(x)=\frac{4x^{3}}{4}-3=x^{3}-3

Step 2 — compare with f(x)f(x): F′(x)=x3−3F'(x)=x^{3}-3 matches f(x)=x3−3f(x)=x^{3}-3 exactly, confirming F(x)F(x) IS an antiderivative of f(x)f(x).

Step 3 — write the indefinite integral: since F(x)F(x) is one antiderivative, every antiderivative of f(x)f(x) differs from it only by a constant:

∫(x3−3) dx=x44−3x+C\int (x^{3}-3)\,dx = \frac{x^{4}}{4}-3x+C

✓Final answer

F(x)=x44−3xF(x)=\dfrac{x^{4}}{4}-3x is confirmed an antiderivative of f(x)=x3−3f(x)=x^{3}-3, and ∫(x3−3) dx=x44−3x+C\displaystyle\int(x^{3}-3)\,dx=\dfrac{x^{4}}{4}-3x+C.

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