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Worked Examples · Example 1

Q.Verify that F(x)=x33+2xF(x) = \dfrac{x^{3}}{3}+2x is an antiderivative of f(x)=x2+2f(x)=x^{2}+2, and hence write down ∫(x2+2) dx\displaystyle\int (x^{2}+2)\,dx.

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✓ Free question

Step 1 — differentiate the candidate F(x)F(x):

F(x)=x33+2x⇒F′(x)=3x23+2=x2+2F(x)=\frac{x^{3}}{3}+2x \quad\Rightarrow\quad F'(x)=\frac{3x^{2}}{3}+2=x^{2}+2

Step 2 — compare with f(x)f(x): F′(x)=x2+2F'(x)=x^{2}+2 matches f(x)=x2+2f(x)=x^{2}+2 exactly, confirming F(x)F(x) IS an antiderivative of f(x)f(x).

Step 3 — write the indefinite integral: since F(x)F(x) is one antiderivative, every antiderivative of f(x)f(x) differs from it only by a constant:

∫(x2+2) dx=x33+2x+C\int (x^{2}+2)\,dx = \frac{x^{3}}{3}+2x+C

✓Final answer

F(x)=x33+2xF(x)=\dfrac{x^{3}}{3}+2x is confirmed an antiderivative of f(x)=x2+2f(x)=x^{2}+2, and ∫(x2+2) dx=x33+2x+C\displaystyle\int(x^{2}+2)\,dx=\dfrac{x^{3}}{3}+2x+C.

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