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Exercises · Q13

Q.A wholesaler's pricing policy is: for an order of xx units, the total cost is C(x)=50xC(x) = 50x rupees if x≤100x \leq 100, and C(x)=45xC(x) = 45x rupees if x>100x > 100 (the lower rate of ₹45 per unit applies to the entire order once it exceeds 100 units, not just the units beyond 100).

(i) Examine the continuity of C(x)C(x) at x=100x=100.
(ii) Compare the total cost of ordering exactly 100 units with the total cost of ordering 101 units, and comment.
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(i) Continuity at x=100x=100.

C(100)C(100): since x≤100x \leq 100 uses the first piece, C(100)=50(100)=₹5,000C(100) = 50(100) = ₹5{,}000.

Left-hand limit (using 50x50x for x≤100x \leq 100, approaching from below): lim⁡x→100−C(x)=50(100)=₹5,000\lim_{x \to 100^{-}} C(x) = 50(100) = ₹5{,}000

Right-hand limit (using 45x45x for x>100x>100, approaching from above): lim⁡x→100+C(x)=45(100)=₹4,500\lim_{x \to 100^{+}} C(x) = 45(100) = ₹4{,}500

Since LHL (₹5,000₹5{,}000) ≠\neq RHL (₹4,500₹4{,}500), lim⁡x→100C(x)\lim_{x \to 100} C(x) does not exist, so C(x)C(x) is discontinuous at x=100x=100 — specifically, a jump discontinuity, since the two one-sided limits genuinely disagree (unlike Exercise 5's removable case).

(ii) Comparing 100 units with 101 units.

At x=100x=100: C(100)=50×100=₹5,000C(100) = 50 \times 100 = ₹5{,}000.

At x=101x=101: since 101>100101>100, the discounted rate applies to the whole order: C(101)=45×101=₹4,545C(101) = 45 \times 101 = ₹4{,}545. …

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