Skip to content
Question 17 of 37

Q.(f) If (x−yz2x−yw)=(−1405)\begin{pmatrix} x-y & z \\ 2x-y & w \end{pmatrix} = \begin{pmatrix} -1 & 4 \\ 0 & 5 \end{pmatrix}, then the respective values of x,y,z,wx, y, z, w are

(a) 1,2,3,41, 2, 3, 4
(b) 1,2,4,51, 2, 4, 5
(c) 1,2,3,51, 2, 3, 5
(d) 1,1,4,51, 1, 4, 5
ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2019MCQ· 1mImportance★★★★★est
46% · 17/37 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Correct option: (b) x=1, y=2, z=4, w=5x=1,\,y=2,\,z=4,\,w=5.

Two matrices are equal iff their corresponding elements are equal. Comparing

(x−yz2x−yw)=(−1405)\begin{pmatrix} x-y & z \\ 2x-y & w \end{pmatrix} = \begin{pmatrix} -1 & 4 \\ 0 & 5 \end{pmatrix}

gives four equations:

x−y=−1,z=4,2x−y=0,w=5.x - y = -1, \quad z = 4, \quad 2x - y = 0, \quad w = 5.

From 2x−y=02x - y = 0 we get y=2xy = 2x. Substitute into x−y=−1x - y = -1: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.