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Worked Examples · Example 4

Q.State which of the following sets are finite and which are infinite.

(i) {x:x∈Z and satisfies the equation (x+1)(x+2)=0}\{x : x \in Z \text{ and satisfies the equation } (x+1)(x+2) = 0\}
(ii) {x:x∈N and x2−1=3}\{x : x \in N \text{ and } x^2 - 1 = 3\}
(iii) {x:x is an odd natural number}\{x : x \text{ is an odd natural number}\}
(iv) {x:x is an integer and −1<x<0}\{x : x \text{ is an integer and } -1 < x < 0\}
(v) {x:x is an integer less than 0}\{x : x \text{ is an integer less than } 0\}
(vi) {x:x satisfies the identity cos⁡2x+sin⁡2x=1}\{x : x \text{ satisfies the identity } \cos^2 x + \sin^2 x = 1\}
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A set is finite if its elements can be counted and the counting process terminates; otherwise it is infinite.

Finite set: has a definite (possibly zero) number of elements. Infinite set: elements cannot be exhausted by counting.

  1. (i) {x∈Z:(x+1)(x+2)=0}\{x\in\mathbb{Z}: (x+1)(x+2)=0\}. Solving: x=−1x=-1 or x=−2x=-2. Only two integers satisfy this. Finite, set ={−1,−2}=\{-1,-2\} (2 elements).
  2. (ii) {x∈N:x2−1=3}\{x\in\mathbb{N}: x^2-1=3\}. x2=4⇒x=±2x^2=4\Rightarrow x=\pm2; since x∈Nx\in\mathbb{N}, only x=2x=2 qualifies (−2∉N-2\notin\mathbb{N}). Finite, set ={2}=\{2\} (1 element).
  3. (iii) {x:x is an odd natural number}={1,3,5,7,… }\{x : x \text{ is an odd natural number}\}=\{1,3,5,7,\dots\}. There is no largest odd natural number. Infinite. …

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