Q.If is r.m.s. speed of molecules in a gas and is the speed of sound waves in the gas, show that is constant and independent of temperature for all diatomic gases.
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Start your 14-day free trial to unlock the full solution →The ratio depends only on the adiabatic index , which is fixed at for all diatomic gases. Since temperature cancels out when forming the ratio, remains constant for all diatomic molecules.
The question asks us to prove something beautiful: that the ratio of molecular speed to sound speed is a universal constant for an entire class of gases. This universality emerges because both speeds scale with temperature in exactly the same way, leaving behind only the intrinsic structure of the molecule.
Why this ratio matters
The r.m.s. speed measures how fast individual molecules dart around in thermal motion. The sound speed measures how quickly a pressure disturbance propagates through the gas as a collective wave. Both depend on temperature, but their ratio reveals something about the gas's internal degrees of freedom—information encoded in , the ratio of specific heats.
Step-by-step demonstration
1. Write the r.m.s. speed from kinetic theory
The root-mean-square speed of molecules comes directly from the equipartition theorem applied to translational kinetic energy:
where is the universal gas constant, the absolute temperature, and the molar mass.
2. Write the speed of sound in the gas
Sound waves in a gas are adiabatic compressions and rarefactions. The Newton-Laplace formula gives:
where is the adiabatic index (ratio of specific heats at constant pressure and volume).
3. Form the ratio
Dividing the two expressions:
Notice that , , and all cancel. The ratio depends only on .
4. Evaluate for diatomic gases
For a diatomic gas at ordinary temperatures (where rotational modes are active but vibrational modes are frozen), the degrees of freedom are:
- 3 translational
- 2 rotational
- Total: 5 active degrees of freedom
This gives:
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