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Q.Twenty-two

(22) teams have entered a knock-out tournament. Calculate
(i) the total number of matches,
(ii) the number of byes, and
(iii) the number of teams in the upper half and in the lower half of the fixture.
Delhi CbseNCERTShort· 3mImportance★★★★★
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For a knock-out tournament with 22 teams, the total matches are 21, the number of byes is 10, and the halves split as 11 teams each.

Understanding Bye Determination in Knock-Out Tournaments

In a knock-out (elimination) tournament, every team except the champion must lose exactly once. That means the total number of matches is always one less than the number of teams — because each match eliminates one team, and only one team remains undefeated at the end.

The real challenge comes when the number of teams is not a power of 2. A power of 2 (2, 4, 8, 16, 32…) creates a perfect bracket where every round has an even number of teams. When you have 22 teams, that's not a power of 2 — the next higher power is 32. The difference, 32 − 22 = 10, tells you how many byes are needed. A bye is essentially a free pass to the next round, given to certain teams so that the remaining number of competitors becomes a power of 2 after the first round.

The half distribution matters because it determines how the fixture is drawn. When N is even, both halves get the same number of teams: N/2 each. For 22 teams, that's 11 in the upper half and 11 in the lower half.

Important

Byes are not given randomly. The standard allotment order is: last team of the lower half, first team of the upper half, last team of the upper half, first team of the lower half — and this cycle repeats until all byes are assigned.

The Calculations

(i) Total number of matches

The formula is straightforward: …

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