Skip to content
More Questions · Q8

Q.Draw a knock-out fixture for 11 teams and calculate the number of matches, the number of byes, and the distribution of byes in the upper and lower halves.

CBSENCERTSubjective· 5mImportance★★★★★
42% · 33/79 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

11 teams, knock-out. Matches = N - 1 = 10. Byes = 16 - 11 = 5.

Upper half = 6 teams (T1–T6) with 2 byes (T1, T6); Lower half = 5 teams (T7–T11) with 3 byes (T11, T7, T10).

Round I has just 3 matches; the fixture then runs 4 → 2 → 1 to the Final.

Concept understanding — why a knock-out needs byes

In a knock-out (elimination) tournament every match eliminates exactly one team. To leave one champion out of N entrants, exactly N-1 teams must be eliminated, so exactly N-1 matches are played. That is why the matches formula needs no drawing at all — it is pure counting.

The bracket, however, halves at every round: 16 → 8 → 4 → 2 → 1. It only works cleanly when the number of teams is a power of 2. When N is not a power of 2, we top the draw up to the next power of 2 by giving some teams a bye — a free pass into Round II without playing Round I.

For N teams in a knock-out tournament:

  • Total number of matches = N - 1
  • Number of byes = (next higher power of 2) - N    (powers of 2: 2, 4, 8, 16, 32, 64 …)
  • If N is itself a power of 2, there are no byes.
  • When N is odd: Upper half = (N+1)/2 teams, Lower half = (N-1)/2 teams.
  • When N is even: each half = N/2 teams.

Here N = 11 (teams), and the answers come out in teams, byes and matches — all pure counts, no units.

Step-by-step calculation

  1. Number of matches

    Matches = N - 1 = 11 - 1 = 10

  2. Number of byes — the powers of 2 are 2, 4, 8, 16, 32 …; the next higher power of 2 above 11 is 16.

    Byes = 16 - 11 = 5

  3. Division into halves (11 is odd)

    Upper half = (N+1)/2 = (11+1)/2 = 6 teams (Teams 1–6)

    Lower half = (N-1)/2 = (11-1)/2 = 5 teams (Teams 7–11)

  4. Distribution of the 5 byes — byes are allotted in the fixed order: last team of the lower half → first team of the upper half → last team of the upper half → first team of the lower half, and then the sequence repeats inwards.

    Bye #Goes toWhich teamHalf
    1stLast team of the lower halfTeam 11Lower
    2ndFirst team of the upper halfTeam 1Upper
    3rdLast team of the upper halfTeam 6Upper
    4thFirst team of the lower halfTeam 7Lower
    5thNext (second-last) of the lower halfTeam 10Lower

    Upper half: 2 byes (T1, T6) Lower half: 3 byes (T11, T7, T10)

  5. Round-I matches — 5 teams sit out, so the teams actually playing Round I are 11 - 5 = 6, i.e. 6 ÷ 2 = 3 matches.

The fixture

Round I — 3 matches (teams with a bye marked bye)

HalfTeamRound I
Upper (6 teams)Team 1bye
Team 2M1: T2 v T3
Team 3M1
Team 4M2: T4 v T5
Team 5M2
Team 6bye
Lower (5 teams)Team 7bye
Team 8M3: T8 v T9
Team 9M3
Team 10bye
Team 11bye

The full bracket (Round I through the final) is shown below. Each half now has 4 teams (a clean power of 2), so the draw runs 4 → 2 → 1 to the final: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.