Skip to content
Exercise 9 · Q9

Q.If aa and bb are positive integers and a−b6.25=82.5\dfrac{a-b}{6.25} = \dfrac{8}{2.5}

(i) b>ab > a
(ii) b<ab < a
(iii) b=ab = a
(iv) b≥ab \ge a
Dnh Dd CbseNCERTSubjective· 1mImportance★★★★★
98% · 104/106 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The equation gives a−b=20a-b = 20, a positive value, so aa exceeds bb; the correct choice is b<ab < a.

Solve for a−ba-b from the given proportion, then compare its sign: if a−b>0a-b>0 then a>ba>b.

  1. Given: a−b6.25=82.5\dfrac{a-b}{6.25} = \dfrac{8}{2.5}, with a,ba,b positive integers.
  2. Evaluate the right side: 82.5=3.2\dfrac{8}{2.5} = 3.2.
  3. Cross-multiply: a−b=3.2×6.25=20a - b = 3.2 \times 6.25 = 20. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.