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Q.If a>ba > b and c<0c < 0, then which of the following is true ? (A) a+c<b+ca + c < b + c (B) a−c<b−ca - c < b - c (C) ac>bcac > bc (D) a−c>b+ca - c > b + c

CBSECBSE Class XII Board 2025MCQ· 1mImportance★★★★★
✓ Free question

Adding/subtracting the same value keeps the direction; multiplying by c<0c<0 reverses it. Only (D) is consistent with a>b, c<0a>b,\ c<0.

If a>ba>b: then a+k>b+ka+k>b+k (adding same kk), and ac<bcac<bc when c<0c<0 (multiplying by a negative flips the sign).

  1. (A) a+ca+c vs b+cb+c: adding cc to both sides of a>ba>b gives a+c>b+ca+c>b+c, so (A) is false.
  2. (B) a−ca-c vs b−cb-c: subtracting the same cc gives a−c>b−ca-c>b-c, so (B) is false.
  3. (C) acac vs bcbc: since c<0c<0, multiplying flips the sign to ac<bcac<bc, so (C) is false.
  4. (D) Compare a−ca-c and b+cb+c: (a−c)−(b+c)=(a−b)−2c(a-c)-(b+c)=(a-b)-2c. Here a−b>0a-b>0 and −2c>0-2c>0 (because c<0c<0), so the difference is positive ⇒a−c>b+c\Rightarrow a-c>b+c.
✓Final answer

The correct statement is a−c>b+ca-c>b+c — option (D).

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