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Q.Identify the logic gates marked P and Q. Rewrite the truth table with output Y for input conditions shown in the truth table for the combination of logic gates and identify the logic operation carried out by the combination of gates. OR A semiconductor X is made by doping a germanium crystal with indium. A second semiconductor Y is made by doping germanium with arsenic. The two are joined end to end and connected to a battery as shown (a diagram shows blocks X and Y joined in series and connected to a battery) :

(i) Identify the semiconductors X and Y obtained after doping.
(ii) Identify the biasing and draw VI characteristics.
(iii) If the polarity of the source is reversed, how will the width of the depletion region change ?
Goa GbshseGBSHSE Class 12 Board Exam 2024Subjective· 4mImportance★★★★★
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Two NOT gates followed by a NAND gate is, by De Morgan's theorem, equivalent to an OR gate.

From the circuit, input A passes through a single-input gate P before reaching the next gate, and input B passes through an identical gate P — a single-input gate that inverts its input is a NOT gate. The outputs of the two NOT gates (i.e. Aˉ\bar A and Bˉ\bar B) feed into a two-input gate Q whose output is Y — a gate producing Aˉ⋅Bˉ‾\overline{\bar A \cdot \bar B} is a NAND gate.

Truth table:

ABAˉ\bar ABˉ\bar BAˉ⋅Bˉ\bar A\cdot\bar BY=Aˉ⋅Bˉ‾Y=\overline{\bar A\cdot\bar B}
001110
011001
100101

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