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Worked Examples · Example 4
Q.

Using the same distribution as the previous example, calculate the median:

Marks0-1010-2020-3030-4040-50
No. of students5812105
Gujarat GsebTextbookSubjectiveImportance★★★★★est
73% · 11/15 Questions
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Cumulative frequency table:

Marksffc.f.
0-1055
10-20813
20-301225
30-401035
40-50540

N=40N=40, so N2=20\dfrac{N}{2}=20. The first cumulative frequency ≥20\geq 20 is 25, occurring in the class 20-30 — this is the median class.

L=20L=20, cf=13cf=13 (c.f. of the PRECEDING class, 10-20), f=12f=12, h=10h=10:

Median=L+(N2−cff)×h=20+(20−1312)×10=20+712×10=20+5.83=25.83\text{Median} = L + \left(\frac{\frac{N}{2}-cf}{f}\right)\times h = 20 + \left(\frac{20-13}{12}\right)\times10 = 20 + \frac{7}{12}\times10 = 20+5.83 = 25.83 …

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