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Worked Examples · Example 3
Q.

Calculate the arithmetic mean of the following continuous distribution using the step-deviation method, and verify using the direct method:

Marks0-1010-2020-3030-4040-50
No. of students5812105
Gujarat GsebTextbookSubjectiveImportance★★★★★
67% · 10/15 Questions
✓ Free question

Step-deviation method: mid-points mm, take A=25A=25 (mid-point of the middle class), h=10h=10, d′=m−Ahd'=\frac{m-A}{h}:

Marksffmmd′=m−2510d'=\frac{m-25}{10}fd′fd'
0-1055-2-10
10-20815-1-8
20-30122500
30-401035110
40-50545210
TotalN=40Σfd′=2\Sigma fd'=2

Xˉ=A+Σfd′N×h=25+240×10=25+0.5=25.5\bar{X} = A + \frac{\Sigma fd'}{N}\times h = 25 + \frac{2}{40}\times10 = 25+0.5 = 25.5

Independent cross-check — direct method:

Σfm=5(5)+8(15)+12(25)+10(35)+5(45)=25+120+300+350+225=1020\Sigma fm = 5(5)+8(15)+12(25)+10(35)+5(45) = 25+120+300+350+225 = 1020

Xˉ=ΣfmN=102040=25.5\bar{X} = \frac{\Sigma fm}{N} = \frac{1020}{40} = 25.5

Both methods agree exactly at Xˉ=25.5\bar{X} = 25.5.

✓Final answer

Arithmetic mean = 25.5 marks (confirmed by both the step-deviation and direct methods).

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