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Exercises · Q8

Q.In a perfectly symmetric distribution, Karl Pearson's coefficient of skewness is:

(a) Positive
(b) Negative
(c) Zero
(d) Equal to 3
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In a perfectly symmetric distribution, Mean = Median = Mode (Section 1 of this chapter). Karl Pearson's coefficient is:

SkP=Mean−ModeσSk_P=\dfrac{\text{Mean}-\text{Mode}}{\sigma}

Since Mean and Mode are equal in a symmetric distribution, the numerator (Mean−Mode)=0(\text{Mean}-\text{Mode})=0, and therefore SkP=0Sk_P=0 regardless of the value of the standard deviation.

Why the other options are wrong:

  • (a) Positive would require Mean > Mode, which contradicts symmetry.
  • (b) Negative would require Mean < Mode, which also contradicts symmetry. …

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