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Exercises · Q9

Q.For a distribution of monthly savings of employees, the mean is Rs. 38 and the median is Rs. 36. The standard deviation is Rs. 8, and the mode cannot be located directly because the distribution is bimodal. Estimate the mode using the empirical relationship, and hence compute Karl Pearson's coefficient of skewness.

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Given: Mean xˉ=38\bar{x}=38, Median Md=36M_d=36, Standard deviation σ=8\sigma=8; mode not directly available (bimodal distribution).

Step 1 — Estimate the mode using the empirical relationship.

Mode=3 Median−2 Mean=3(36)−2(38)=108−76=32\text{Mode}=3\,\text{Median}-2\,\text{Mean} = 3(36)-2(38)=108-76=32

Step 2 — Karl Pearson's coefficient using the estimated mode.

SkP=xˉ−Modeσ=38−328=68=0.75Sk_P=\dfrac{\bar{x}-\text{Mode}}{\sigma}=\dfrac{38-32}{8}=\dfrac{6}{8}=0.75

Independent check — median-based formula. Since the mode used above was itself derived from the empirical relationship, algebra guarantees that (xˉ−Mode)=3(xˉ−Md)(\bar{x}-\text{Mode})=3(\bar{x}-M_d) exactly. Confirming directly: 3(xˉ−Md)=3(38−36)=63(\bar{x}-M_d)=3(38-36)=6, and 68=0.75\dfrac{6}{8}=0.75 — identical to Step 2, as it must be whenever the mode used is the empirically estimated one (this is precisely why the median-based formula exists — it is just this substi …

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