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Question 42 of 46

Q.For a normal distribution, approximate value of mean deviation is 20. Which of the following is the value of quartile deviation?

(a) 253\dfrac{25}{3}
(b) 323\dfrac{32}{3}
(c) 2424
(d) 503\dfrac{50}{3}
Gujarat GsebGujarat Board (GSEB) HSC Commerce Board 2026MCQ· 1mImportance★★★★★
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Using QD:MD:SD=10:12:15QD:MD:SD=10:12:15, QD=1012(20)=503QD=\tfrac{10}{12}(20)=\tfrac{50}{3}.

For a normal distribution the approximate relations are QD≈23σQD\approx\tfrac23\sigma and MD≈45σMD\approx\tfrac45\sigma, giving QD:MD:SD=10:12:15QD:MD:SD=10:12:15. Therefore

QD=1012×MD=1012×20=20012=503.QD=\frac{10}{12}\times MD=\frac{10}{12}\times20=\frac{200}{12}=\frac{50}{3}. …

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