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Q.In a factory which manufactures bolts, machines A, B and C manufacture respectively 25%, 35% and 40% of the bolts of their outputs, 5, 4 and 2 percent are respectively defective bolts. A bolt is drawn at random from the product and is found to be defective. What is the probability that it is manufactured by the machine B?

Gujarat GsebGSEB Higher Secondary Certificate (HSC) Examination 2024Subjective· 3mImportance★★★★★
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This is a direct Bayes'-theorem problem: use the law of total probability for the denominator, then Bayes' formula for the required conditional probability.

Let A1,A2,A3A_1,A_2,A_3 = bolt from machine A, B, C, with P(A1)=0.25P(A_1)=0.25, P(A2)=0.35P(A_2)=0.35, P(A3)=0.40P(A_3)=0.40.

Let DD = bolt is defective, with P(D∣A1)=0.05P(D|A_1)=0.05, P(D∣A2)=0.04P(D|A_2)=0.04, P(D∣A3)=0.02P(D|A_3)=0.02.

By the law of total probability:

P(D)=P(A1)P(D∣A1)+P(A2)P(D∣A2)+P(A3)P(D∣A3)P(D)=P(A_1)P(D|A_1)+P(A_2)P(D|A_2)+P(A_3)P(D|A_3)

=0.25(0.05)+0.35(0.04)+0.40(0.02)=0.0125+0.014+0.008=0.0345=0.25(0.05)+0.35(0.04)+0.40(0.02)=0.0125+0.014+0.008=0.0345.

By Bayes' theorem: …

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