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Q.Derive equation for a potential energy of a dipole in an external electric field.

Gujarat GsebGSEB Higher Secondary Certificate (HSC) Examination 2026Subjective· 3mImportance★★★★★
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The potential energy of a dipole is the negative of the work done by the field's torque in rotating the dipole from a chosen reference orientation to the given angle theta, giving U = -p E cos(theta).

Consider a dipole of moment p placed in a uniform external field E, making angle theta with the field. The torque on the dipole is tau = p E sin(theta), which tends to rotate the dipole to align with the field (theta = 0).

Work done by an external agent to rotate the dipole from angle theta_1 to theta_2 against this torque (quasi-statically) is:

W = integral from theta_1 to theta_2 of [p E sin(theta)] d(theta) = p E [-cos(theta)] from theta_1 to theta_2 = p E (cos theta_1 - cos theta_2)

This work equals the change in potential energy, W = U(theta_2) - U(theta_1). Choosing the reference orientation theta_1 = 90 degrees (dipole perpendicular to field) as the zero of potential energy (U(90 deg) = 0, since cos 90 deg = 0):

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