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Q.Two point charges +10 μC+10\ \mu C and −10 μC-10\ \mu C are situated 2 cm apart. This dipole is placed in a uniform electric field of 1×1051 \times 10^{5} volt/metre. Calculate the energy required to rotate the dipole from the position of 0∘0^\circ to 180∘180^\circ.

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2026Subjective· 2mImportance★★★★★
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Using W=pE(cos⁡θ1−cos⁡θ2)W = pE(\cos\theta_1-\cos\theta_2) with a 0∘→180∘0^\circ\to180^\circ flip, W=2pE=0.04W = 2pE = 0.04 J.

Concept. The work done in rotating an electric dipole in a uniform field from angle θ1\theta_1 to θ2\theta_2 equals the change in its potential energy:

W=pE(cos⁡θ1−cos⁡θ2),W = pE(\cos\theta_1 - \cos\theta_2),

where p=q×(2a)p = q\times(2a) is the dipole moment.

Calculation. Dipole moment:

p=q(2a)=(10×10−6)(2×10−2)=2×10−7 C⋅m.p = q(2a) = (10\times10^{-6})(2\times10^{-2}) = 2\times10^{-7}\ \text{C·m}. …

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