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Q.(a) An electric dipole with dipole moment 4 × 10^-9 cm is aligned at 30° with the direction of a uniform electric field of magnitude 5 × 10^4 NC^-1. Calculate the magnitude of the torque acting on the dipole.

(2)
(b) The maximum value of torque experienced by the dipole will be when it is aligned at an angle θ = ________. (1)
Kerala DhseKerala DHSE Plus Two Board 2026Subjective· 3mImportance★★★★★
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The torque on a dipole is τ=pEsin⁡θ\tau = pE\sin\theta; here it works out to 10−410^{-4} N·m at 30°, and the torque is maximum when the dipole is perpendicular to the field (θ = 90°).

(a) The torque on an electric dipole of moment pp placed at angle θ to a uniform field E is

τ=pEsin⁡θ\tau = pE\sin\theta

Given p=4×10−9p = 4\times10^{-9} C·m, E=5×104E = 5\times10^4 N/C, θ=30°\theta = 30°:

τ=(4×10−9)(5×104)sin⁡30°=(4×10−9)(5×104)(0.5)\tau = (4\times10^{-9})(5\times10^4)\sin30° = (4\times10^{-9})(5\times10^4)(0.5)

τ=1×10−4 N⋅m\tau = 1\times10^{-4}\ \text{N·m}

(b) Since τ=pEsin⁡θ\tau = pE\sin\theta, torque is maximum when sin⁡θ=1\sin\theta = 1, i.e. when the dipole moment is perpendicular to the field, θ=90°\theta = 90°.

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