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Q.Find the ratio in which the line joining the points (4,8,10)(4, 8, 10) and (6,10,−8)(6, 10, -8) is divided by the YZ-plane.

Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2018Subjective· 4mImportance★★★★★
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Setting the section-formula xx-coordinate to 0 (the YZ-plane's equation) and solving for the ratio gives a negative value, meaning the division is external.

Let the YZ-plane divide the segment joining P(4,8,10)P(4,8,10) and Q(6,10,−8)Q(6,10,-8) in the ratio k:1k:1 (measured from PP to QQ). By the section formula, the xx-coordinate of the dividing point is:

x=k(6)+1(4)k+1x = \frac{k(6) + 1(4)}{k+1}

Since the YZ-plane is x=0x=0, set this equal to 0:

6k+4k+1=0  ⇒  6k+4=0  ⇒  k=−46=−23\frac{6k+4}{k+1} = 0 \;\Rightarrow\; 6k+4 = 0 \;\Rightarrow\; k = -\frac{4}{6} = -\frac{2}{3}

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