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Q.Prove that P(3, 2, -4), Q(5, 4, -6) and R(9, 8, -10) are collinear. Also find the ratio in which Q divides PR.

Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2023Subjective· 6mImportance★★★★★
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Show the direction vectors PQ⃗\vec{PQ} and QR⃗\vec{QR} are parallel (one is a scalar multiple of the other) to prove collinearity, then use the section formula to find the ratio.

Given P(3,2,−4)P(3,2,-4), Q(5,4,−6)Q(5,4,-6), R(9,8,−10)R(9,8,-10).

Collinearity:

PQ⃗=Q−P=(5−3, 4−2, −6−(−4))=(2,2,−2)\vec{PQ} = Q-P = (5-3,\,4-2,\,-6-(-4)) = (2,2,-2)

QR⃗=R−Q=(9−5, 8−4, −10−(−6))=(4,4,−4)\vec{QR} = R-Q = (9-5,\,8-4,\,-10-(-6)) = (4,4,-4)

Since QR⃗=2PQ⃗\vec{QR}=2\vec{PQ}, the vectors are parallel; and they share the common point QQ. Therefore PP, QQ, RR lie on the same straight line — they are collinear.

Ratio in which Q divides PR: Let QQ divide PRPR in the ratio k:1k:1 (from PP towards RR). By the section formula:

Q=(kR+Pk+1)Q = \left(\frac{kR+P}{k+1}\right) …

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