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Q.Mean Deviation about mean of 5, 8, 9, 10, 11, 13, 14, 18 is:

(a) 2.5
(b) 3
(c) 3.5
(d) 4
Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2025MCQ· 1mImportance★★★★★
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Find the mean, take absolute deviations of each value from it, then average those deviations.

Data: 5,8,9,10,11,13,14,185, 8, 9, 10, 11, 13, 14, 18 (n=8n=8).

Mean xˉ=5+8+9+10+11+13+14+188=888=11\bar x = \dfrac{5+8+9+10+11+13+14+18}{8} = \dfrac{88}{8} = 11

Absolute deviations ∣xi−xˉ∣|x_i - \bar x|: 6,3,2,1,0,2,3,76, 3, 2, 1, 0, 2, 3, 7

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