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Q.Find the mean deviation about mean for the following data: 4,7,8,9,10,12,13,174, 7, 8, 9, 10, 12, 13, 17

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2026Subjective· 3mImportance★★★★★
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The mean deviation about the mean is 33.

Data: 4,7,8,9,10,12,13,174, 7, 8, 9, 10, 12, 13, 17 (n=8n=8).

Step 1 — Mean:

xˉ=4+7+8+9+10+12+13+178=808=10\bar{x} = \dfrac{4+7+8+9+10+12+13+17}{8} = \dfrac{80}{8} = 10

Step 2 — Absolute deviations from the mean:

∣4−10∣=6, ∣7−10∣=3, ∣8−10∣=2, ∣9−10∣=1, ∣10−10∣=0, ∣12−10∣=2, ∣13−10∣=3, ∣17−10∣=7|4-10|=6,\ |7-10|=3,\ |8-10|=2,\ |9-10|=1,\ |10-10|=0,\ |12-10|=2,\ |13-10|=3,\ |17-10|=7

Step 3 — Sum of deviations:

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