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Q.The vertices of a Δ PQR are P(2, 1), Q(-2, 3) and R(4, 5). Find equation of the median through the vertex R and Q. OR Find the distance between the parallel lines 15x + 8y - 34 = 0 and 15x + 8y + 31 = 0.

Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2024Subjective· 5mImportance★★★★★
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Median from R goes to the midpoint of PQ, giving 3x−4y+8=03x-4y+8=0; median from Q goes to the midpoint of PR, giving the horizontal line y=3y=3.

Vertices: P(2,1)P(2,1), Q(−2,3)Q(-2,3), R(4,5)R(4,5).

Median through R (from RR to the midpoint of the opposite side PQPQ):

Midpoint of PQPQ =(2+(−2)2,1+32)=(0,2)= \left(\dfrac{2+(-2)}2,\dfrac{1+3}2\right) = (0,2).

Line through R(4,5)R(4,5) and (0,2)(0,2): slope =5−24−0=34=\dfrac{5-2}{4-0}=\dfrac34.

y−2=34(x−0)⇒4y−8=3x⇒3x−4y+8=0y-2 = \dfrac34(x-0) \Rightarrow 4y-8=3x \Rightarrow 3x-4y+8=0.

Median through Q (from QQ to the midpoint of the opposite side PRPR): …

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