Q.Transform the equation 3x+4y=5 into
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Various Forms of the Equation of a Line
Imagine you want to describe a straight line to someone who has never seen it. You could say "it goes through this point and slants like this" — that's the intuition. In coordinate geometry, we capture that same idea using equations. A line is just the set of all points (x,y) that satisfy a certain condition. Different conditions give us different forms of the same line.
1. Slope-Intercept Form: y=mx+c
This is the most familiar form. Here m is the slope (steepness) and c is the y-intercept (where the line cuts the y-axis).
Why it works: If you know how much the line rises for every unit it runs horizontally (m), and where it starts on the y-axis (c), you can write the equation directly.
To find m: pick any two points (x1,y1) and (x2,y2) on the line, then m=x2−x1y2−y1.
Example: A line with slope 2 and y-intercept -3 is y=2x−3.
2. Point-Slope Form: y−y1=m(x−x1)
Suppose you know the slope m and one point (x1,y1) on the line. The point-slope form says: the difference in y from that point equals the slope times the difference in x.
Intuition: If you stand at (x1,y1) and move horizontally by (x−x1), you must move vertically by m times that amount to stay on the line.
y−y1=m(x−x1)
Example: Line through (2,5) with slope −4: y−5=−4(x−2).
3. Two-Point Form: y2−y1y−y1=x2−x1x−x1
If you know two points (x1,y1) and (x2,y2), you don't need to compute slope separately. This form says the ratio of vertical change to total vertical span equals the ratio of horizontal change to total horizontal span.
Why it's natural: It's just the condition that the three points (x1,y1), (x2,y2), and (x,y) are collinear — they all lie on the same straight line.
If x1=x2 or y1=y2, the denominator becomes zero. That's fine — it just means the line is vertical or horizontal. Use the appropriate special form instead.
Example: Line through (1,2) and (3,8): 8−2y−2=3−1x−1, which simplifies to y=3x−1.
4. Intercept Form: ax+by=1
Here a is the x-intercept (where the line cuts the x-axis) and b is the y-intercept.
Intuition: When y=0, the equation gives x=a; when x=0, it gives y=b. So the line passes through (a,0) and (0,b).
This form only works if the line cuts both axes (i.e., a=0 and b=0). A line through the origin cannot be written this way.
Example: A line with x-intercept 4 and y-intercept -3: 4x+−3y=1, or 4x−3y=1.
5. Normal Form: xcosθ+ysinθ=p
This is the most geometric form. Here p is the perpendicular distance from the origin to the line, and θ is the angle that this perpendicular makes with the positive x-axis.
Why it's useful: It directly gives the distance of the line from the origin — something the other forms hide.
| Form | When to use |
|------|-------------|
| Slope-intercept | Slope and y-intercept known |
| Point-slope | Slope and one point known |
| Two-point | Two points known | …
Isolating y in 3x+4y=5 gives slope-intercept form, while dividing throughout by the constant term gives intercept form. …
Rearranging 3x+4y=5 isolates y for slope-intercept form, and dividing by the constant term gives intercept form.
- Slope-intercept form y=mx+c: From 3x+4y=5, 4y=−3x+5, so y=−43x+45 Here slope m=−43 and y-intercept c=45.
- Intercept form ax+by=1: Divide 3x+4y=5 throughout by 5: …
- CBSE 2025Set ANNUAL1 markMCQQ.Intercept form of a straight line is(a) ax+by=1(b) ax−by=1(c) ax+by=−1(d) None of these
›Reveal solutionSolution
The intercept form of a line with x-intercept a and y-intercept b is ax+by=1.
A line that cuts the x-axis at (a,0) and the y-axis at (0,b) has the equation:
ax+by=1
…
- CBSE 2024Set ANNUAL1 markMCQQ.Find the equation of the straight line which passes through the point (3,4) and whose x-intercept is equal to y-intercept.(a) x+y=7(b) x+y=3(c) x−y=2(d) None of these
›Reveal solutionSolution
A line with equal x- and y-intercepts (both =a) has the form x+y=a; substitute the given point to find a.
If a line has x-intercept =y-intercept =a, its intercept form ax+ay=1 simplifies to:
x+y=a
Since the line passes through (3,4), substitute:
3+4=a⟹a=7
So the equation of the line is:
x+y=7
…
- CBSE 2022Set ANNUAL1 markQ.The equation of line passing through (1, 2) and slope 3 is ............ .
›Reveal solutionSolution
Using point-slope form with point (1,2) and slope 3 gives 3x−y−1=0.
Point-slope form of a line through (x1,y1) with slope m:
y−y1=m(x−x1)
With (x1,y1)=(1,2) and m=3:
y−2=3(x−1) …
- CBSE 2021Set ANNUAL1 markMCQQ.The equation of line passing through (2, 3) and making an angle 45° with positive x-axis is:(a) x − y + 1 = 0(b) x + y − 5 = 0(c) x + y − 1 = 0(d) None of these
›Reveal solutionSolution
Slope =tan45°=1; point-slope form through (2,3) reduces to x−y+1=0.
Slope of a line making angle 45° with the positive x-axis: m=tan45°=1.
Point-slope form through (2,3):
…
- CBSE 2020Set ANNUAL1 markMCQQ.Find the equation of the straight line which passes through the point (2,3) and cut off equal intercepts on the axes.(a) x+y=4(b) x+y=5(c) x+y=6(d) 2x+3y=9
›Reveal solutionSolution
A line with equal intercepts a on both axes has the equation x+y=a; substitute the given point to find a.
Intercept form of a line with equal intercepts a on the x- and y-axes: ax+ay=1, i.e. x+y=a.
…
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