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Q.The molecule of a monoatomic gas has only three translational degrees of freedom. Thus, the average energy of a molecule at temperature T is (3/2)KT. The total internal energy of a mole of such a gas is U = (3/2)RT. The molar specific heat at constant volume Cv is given by Cv = dU/dT = (3/2)R. For an ideal gas Cp − Cv = R, where Cp is the molar specific heat at constant pressure. Thus Cp = (5/2)R.

(i) For diatomic molecules ratio of specific heat is:
(a) 3/5
(b) 5/7
(c) 5/3
(d) 7/5.
(ii) The value of Cv for one mole of neon gas is:
(a) R/2
(b) 3R/2
(c) 5R/2
(d) 7R/2.
(iii) The temperature of an ideal gas is increased from 27°C to 927°C. What is the effect on r.m.s. speed of its molecules? [Sub-part
(iii) carries an internal choice — see or_stem.] OR
(iii) alternative: State Law of Equipartition of Energy.
Haryana BsehBoard of School Education Haryana (Senior Secondary Part-I / Class 11) 2025Subjective· 4mImportance★★★★★
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Diatomic gases have two extra rotational degrees of freedom beyond the three translational ones, pushing their Cp/CvC_p/C_v ratio down to 7/5; a monatomic gas like neon has only Cv=3R/2C_v=3R/2; and since r.m.s. speed depends on T\sqrt T (absolute temperature), a 4× rise in T means a 2× rise in speed.

(i) Ratio of specific heats for diatomic molecules:

A diatomic molecule has 5 degrees of freedom: 3 translational + 2 rotational (about the two axes perpendicular to the bond axis).

By the law of equipartition of energy, average energy per molecule =(5/2)kT= (5/2)kT, so for one mole: U=(5/2)RTU = (5/2)RT.

Cv=dU/dT=(5/2)RC_v = dU/dT = (5/2)R

Cp=Cv+R=(5/2)R+R=(7/2)RC_p = C_v + R = (5/2)R + R = (7/2)R

γ=Cp/Cv=(7/2)R÷(5/2)R=7/5\gamma = C_p/C_v = (7/2)R \div (5/2)R = 7/5

Answer: option (d) 7/5

(ii) CvC_v for neon (a monatomic gas):

Neon has only 3 translational degrees of freedom (monatomic), so as given in the passage:

Cv=(3/2)RC_v = (3/2)R

Answer: option (b) 3R/2

(iii) Effect on r.m.s. speed when temperature rises from 27°C to 927°C:

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