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Q.There are three coins. One is a two headed coin (having head on both sides), another is a biased coin that comes up head 60%60\% of the time and third is an unbiased coin. One of the three coins is chosen at random and tossed. If head occurs what is the probability that it is the two headed coin.

Haryana BsehBSEH Intermediate Board 2023Subjective· 4mImportance★★★★★
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Apply Bayes' theorem with equal prior 13\tfrac13 for each coin.

Let C1C_1 = two-headed coin, C2C_2 = biased coin (60%60\% heads), C3C_3 = unbiased coin. Each is chosen with prior probability P(Ci)=13P(C_i)=\dfrac13.

P(H∣C1)=1,P(H∣C2)=0.6=35,P(H∣C3)=0.5=12P(H\mid C_1)=1,\quad P(H\mid C_2)=0.6=\dfrac35,\quad P(H\mid C_3)=0.5=\dfrac12

By the law of total probability:

P(H)=P(C1)P(H∣C1)+P(C2)P(H∣C2)+P(C3)P(H∣C3)=13(1)+13(35)+13(12)P(H)=P(C_1)P(H|C_1)+P(C_2)P(H|C_2)+P(C_3)P(H|C_3)=\dfrac13(1)+\dfrac13\left(\dfrac35\right)+\dfrac13\left(\dfrac12\right)

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