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Q.[Case study, same setup as above — probability of solving: Ravi 30%, Mohit 25%, Sonia 45%; probability of making an error: Ravi 1%, Mohit 1.2%, Sonia 2%] If the solution of the question is checked by the teacher and has some error, then find the probability that the question is not solved by Ravi.

Haryana BsehBSEH Intermediate Board 2024Subjective· 2mImportance★★★★★
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Use Bayes' theorem to find P(R∣E)P(R\mid E) (Ravi solved it, given an error occurred), then subtract from 1 to get P(not R∣E)P(\text{not }R \mid E).

Step 1 — Recall the given/derived probabilities.

From the same setup as the previous sub-part:

P(R)=0.30, P(M)=0.25, P(S)=0.45P(R) = 0.30,\ P(M) = 0.25,\ P(S) = 0.45

P(E∣R)=0.01, P(E∣M)=0.012, P(E∣S)=0.02P(E\mid R) = 0.01,\ P(E\mid M) = 0.012,\ P(E\mid S) = 0.02

and the total probability of an error (computed via the Law of Total Probability) is

P(E)=P(R)P(E∣R)+P(M)P(E∣M)+P(S)P(E∣S)=0.003+0.003+0.009=0.015P(E) = P(R)P(E\mid R) + P(M)P(E\mid M) + P(S)P(E\mid S) = 0.003 + 0.003 + 0.009 = 0.015

Step 2 — Apply Bayes' theorem to find P(R∣E)P(R \mid E).

Bayes' theorem gives the probability that Ravi solved it, given that an error is observed:

P(R∣E)=P(R) P(E∣R)P(E)=0.30×0.010.015=0.0030.015=0.2P(R \mid E) = \frac{P(R)\,P(E \mid R)}{P(E)} = \frac{0.30 \times 0.01}{0.015} = \frac{0.003}{0.015} = 0.2

Step 3 — Find the complementary probability. …

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