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Q.[Case study] In a school, a teacher asks a question to three students Ravi, Mohit and Sonia. The probability of solving the question by Ravi, Mohit and Sonia are 30%, 25% and 45% respectively. The probability of making an error by Ravi, Mohit and Sonia are 1%, 1.2% and 2% respectively. Find the total probability of committing an error in solving the question.

Haryana BsehBSEH Intermediate Board 2024Subjective· 2mImportance★★★★★
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Use the Law of Total Probability: sum, over each student, the chance that student attempts the question times the chance that student makes an error.

Step 1 — Define the events.

Let RR, MM, SS be the events that the question is solved by Ravi, Mohit, and Sonia respectively (these are mutually exclusive and exhaustive, since exactly one of the three attempts it), and let EE be the event that an error is made. We are given:

P(R)=0.30,P(M)=0.25,P(S)=0.45P(R) = 0.30,\quad P(M) = 0.25,\quad P(S) = 0.45

P(E∣R)=0.01,P(E∣M)=0.012,P(E∣S)=0.02P(E \mid R) = 0.01,\quad P(E \mid M) = 0.012,\quad P(E \mid S) = 0.02

Step 2 — Apply the Law of Total Probability.

Since R,M,SR, M, S partition the sample space,

P(E)=P(R) P(E∣R)+P(M) P(E∣M)+P(S) P(E∣S)P(E) = P(R)\,P(E\mid R) + P(M)\,P(E\mid M) + P(S)\,P(E\mid S)

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