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Q.If a plant has genotype AaBb, what will be the possible number of gametes it may produce?

(a) 1
(b) 2
(c) 3
(d) 4
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Number of gamete types = 2ⁿ, where n = number of heterozygous gene pairs. For AaBb, n = 2, so 2² = 4 gamete types.

A plant with genotype AaBb is heterozygous at two independently assorting gene loci (A/a and B/b). During meiosis, each gene pair segregates independently (Law of Independent Assortment), and the alleles combine randomly into gametes. The possible combinations are:

AB, Ab, aB, ab

…

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