Skip to content
Question of 87

Q.Explain:

(i) Aldol condensation
(ii) Coupling Reaction.
Himachal HpboseHPBOSE Plus Two Board 2018Subjective· 2mImportance★★★★★
0% · 0/87 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Aldol condensation builds a C=C bond by combining two carbonyl-bearing molecules with loss of water; coupling reaction links a diazonium salt to an aromatic ring to form a coloured azo dye.

(i) Aldol Condensation

Aldehydes/ketones possessing at least one α-hydrogen atom react with a dilute base (e.g., dil. NaOH) in a two-step process:

  1. Two molecules of the carbonyl compound combine — the enolate (formed by removal of an α-H) attacks the carbonyl carbon of another molecule — giving a β-hydroxy aldehyde/ketone (the 'aldol').
  2. On heating, this aldol readily loses a water molecule (dehydration) to give an α,β-unsaturated carbonyl compound.

Example:

2CH3CHO→dil. NaOHCH3CH(OH)CH2CHO→Δ, −H2OCH3CH=CHCHO2CH_3CHO \xrightarrow{dil.\,NaOH} CH_3CH(OH)CH_2CHO \xrightarrow{\Delta,\,-H_2O} CH_3CH=CHCHO

(acetaldehyde → aldol → crotonaldehyde)

(ii) Coupling Reaction …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.