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Q.Derive an expression for the displacement, velocity and acceleration of a particle executing Simple Harmonic motion.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2023Subjective· 5mImportance★★★★★
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Differentiating the SHM displacement equation x = A sin(wt + phi) once gives velocity, and again gives acceleration, showing acceleration is proportional to and directed opposite to displacement (a = -w^2 x).

Consider a particle executing Simple Harmonic Motion (SHM) with amplitude A, angular frequency w, and initial phase (phase constant) phi.

Displacement:

The displacement of the particle at time t, measured from the mean (equilibrium) position, is given by:

x(t) = A sin(wt + phi)

Velocity:

Velocity is the time derivative of displacement:

v(t) = dx/dt = A w cos(wt + phi)

This can also be expressed in terms of the displacement x itself. Since sin^2 + cos^2 = 1, cos(wt+phi) = sqrt(1 - sin^2(wt+phi)) = sqrt(1 - (x/A)^2). Substituting:

v = A w sqrt(1 - (x^2/A^2)) = w sqrt(A^2 - x^2)

Acceleration:

Acceleration is the time derivative of velocity:

a(t) = dv/dt = -A w^2 sin(wt + phi)

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